62
Lokesh Verma
·2009-09-16 08:28:56
see I think you are talking about P(A2) is the probability of recieveing a letter at the 2nd stage!
If he sends the first letter... Probab that he receives the 2nd is (1/n){1 - (2/n)2}
If someone else sends the first letter...
Probability that he recieves the 1st letter is (1-1/n)(2/n)
Probability that he recieves the 2nd letter given that he recieves the 1st letter is (1-1/n)(2/n) {2/n}
Probability that he does not receive the 1st letter is (1-1/n)(1-2/n)
Probability that he recieves the 2nd letter given that he does not receive the 1st letter is (1-1/n)(1-2/n) {1-(1-2/n)2}
I hope this time it is correct?
24
eureka123
·2009-09-17 02:44:45
its confusing explaiantion.................
cna u expalin a bit more. ???
3
msp
·2009-09-17 04:56:59
1) it is (n-2/n-1)2
2)(n-2/n-1)4 and P(P2 doesnt receives letter at the third stage)=(n-2/n-1)8
3)from the above three relations we can conclude tha
P(Am/A2A3.....Am-1)=(n-2/n-1)2m-1
4) so for m stages requird probability=P(A2).(P3/A2∩A1).......P(Am/A2A3.....Am-1)
24
eureka123
·2009-11-12 02:53:28
Explain all the above answers....
and
Q5 Find probablity that P3 will rite to P1
24
eureka123
·2009-11-13 00:23:03
Plzzzzzzzzzzz.............[75]