If 10 things are distributed among 3 persons,the chance of a particular person having more than 5 of them is 1507/19683
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1 Answers
Lokesh Verma
·2009-01-08 07:45:38
wow that is some fraction!
each one getting less than 5
1+4+5 = 10C1. 9C4. 3! = (10.9.8.7.6) / 4
2+4+4 = 10C2. 8C4. 3 = (10.9.8.7.6.5)/16
2+3+5 = 10C2. 8C3. 3! = (10.9.8.7.6) /2
3+3+4 = 10C3. 7C3 . 3 = (10.9.8.7.6.5)/12
Now try to get this one...