Prog

Suppose t_r=1²+2²+........+r²
let t₁+t₂+........+t_n=1/12 n(n+1)(n+2)k

Find value of k ,

1 Answers

well,dude,t_r = r(r+1) (2r+1)/6

if u do summation of t_r,then u hv to expand it to get : summation (2r³ +3r² +r / 6)

now,apply formulas for summation of t,t²,t³ etc.

u'll get summation t_r = 1/12[ n(n+1)²(n+2)]

now,cn get the answer

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