Prove it..

If a₁'s are all +ve real numbers then prove that:
(1+a₁+a₁²)(1+a₂+a₂²).........((1+a_n+a_n²)â‰¥3ⁿa₁a₂..........a_n

2 Answers

apply AM GM on 1, ai, ai²

(1+a₁+a₁²)/3>=(1.a1.a1²)^1/3

thus,

(1+a₁+a₁²)>=3a1

now multiply this for all ai's

thus the final result :)

Thanx.............It was easy..........

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