prove that

Prove that the eqn

cos 2x + a sinx = 2a- 7

possesses a solution if 2≤a≤6 .

1 Answers

11
SANDIPAN CHAKRABORTY ·

cos 2x + a sin x = 2a - 7

1 - 2 sin 2 x + a sin x - 2a + 7 = 0

so 2 sin 2 x - a sin x + 2a - 8 = 0

sin x = a ± √a2 - 8(2a - 8)4

= a ± (a-8)4

=2a - 84 (taking + sign.we discard - sign as sin x cannot be greater than 1)

= a - 4 2

now -1 ≤ sin x ≤ 1

so -1 ≤ a - 4 2 ≤ 1

so 2 ≤ a ≤ 6

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