Pure G.I.F. business....

JEE Mains Discussion Forum › Algebra questions › Pure G.I.F. business....

Find [1+\frac{1}{2}+\frac{1}{3}+....\frac{1}{121}]
[] â‰¡ G.I.F

#Mathematics #Algebra

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7 Answers

62

Lokesh Verma ·2009-09-21 08:21:25

integral will be ln 120

so the answer will be ln (120) approximately

so it will be 4:)

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24

eureka123 ·2009-09-21 10:07:43

how did u find that ??

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66

kaymant ·2009-09-21 18:32:15

@Nishant, the correct answer is 5.

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62

Lokesh Verma ·2009-09-23 08:32:16

oops.. my approximation failed :(

sob sob...

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39

Dr.House ·2009-09-23 08:35:02

:P , but ln 120 is the common mistake made..

i will post answere if nobody does it by tomorrow..

hope u do it nishant sir....

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62

Lokesh Verma ·2009-09-23 08:37:44

I know my mistake.. but the only thing was that i should have removed 1 first.. :P

that would have given a better result...

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39

Dr.House ·2009-09-23 08:39:22

yes u are right... wasnt pn pointing u (but i too made same mistake first time i solved it)

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω