quad sums -- part 3

all values for which b(b+1)=2
i.e -2,1
and c=1
a,b,c are usual coefficients of quadratic.

i did by squaring function
ax+c=-b√x
and compared coefficients with thw original quadrativ
ax2+bx+c=0
so we get 1=1 c=1

so its is obvius that
(x-1)²=0
has roots 1,1 and also square is 1,1
for the value
1
we get
(x-w)(x-w²)
this is also obvious
roots are
w,w²
and
w²,(w⁴=1.w)
hope ur question is solved

also, x²=0, x²-x=0