Q1) 4x - 3(x - 0.5) = 3(x + 0.5) - 2(2x - 1)
=> 4x - 3x.3-0.5 = 3x.30.5 - 4x.2-1
=> 4x(1 + 2-1) = 3x(30.5 + 3-0.5)
=> 4x.3/2 = 3x.4/30.5
=> 4x/3x = 8/33/2
=> (4/3)x = (4/3)3/2
=> x = 3/2 or, x = 1.5
The answer of Q2. is maybe.. 10 or 1
Q1)Solve: 4x - 3(x-1/2)= 3(x-1/2)-2(2x-1)
Q2)If (1-p)is the root of quadratic equation x2+px+(1-p)=0.the the roots are??
Q3)Inthe proof of common roots it is given for
eq1:aα2+bα+c=0
eq2:a'α2+b'α+c'=0
by cross multiplying we get;
α2/(bc'-b'c)=α/(ca'-ac')=1/(ab'-a'b)
Here α is the common root
Someone pls explain the cross multiplying part.How did we get it??
2)1±√7i/2
3)use simultaneous solutio for 2 equation
1)
x=2log2-1.5log3/2log2-log3
Q1) 4x - 3(x - 0.5) = 3(x + 0.5) - 2(2x - 1)
=> 4x - 3x.3-0.5 = 3x.30.5 - 4x.2-1
=> 4x(1 + 2-1) = 3x(30.5 + 3-0.5)
=> 4x.3/2 = 3x.4/30.5
=> 4x/3x = 8/33/2
=> (4/3)x = (4/3)3/2
=> x = 3/2 or, x = 1.5
The answer of Q2. is maybe.. 10 or 1
@rahul read the question carefully . there is only minus sign in the power to 3.
Dont manipulate the question........
I think cross multiplication is like determinants expansion. Just with a minus sign for the middle term (i.e., α ) and for the rest multiply criss cross as you do while expanding a det.