36no such a and b exists....!!
reason why i feel so....
clearly,
a > 0 , b > 0
a,b are integers
a2 - 4b > 0 and b2 - 4a > 0
on subtracting and arranging we get a > b and b > a ...
how can this be possible for real a and b ?
x^2 - a*x + b = 0
x^2 - b*x + a = 0
Both these equations have positive,integral and distinct roots. Find a and b.
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3 Answers
36
1yes,its true. if it wasn't distinct. then a.b could have been 4,4