quadratic expressions

1.find the condition that the expression ax2+2hxy+by2 may have two factors of the form (y-mx) and (my+x) respectively.

ans: a+b=0

2.find the condition that ax2+2hxy+by2 and a1x2+2h1xy+b1y2 may have factors of the form (y-mx) and (my+x) respectively.

ans:(aa1-bb1)2+4(bh1+a1h)(b1h+ah1)=0

3.if x is real,prove that the expression (x-a)(x-c)/(x-b) is capable of assuming all values if a,b,c are either in increasing or in decreasing order of magnitude.

3 Answers

1
sharadapanda ·

koi to reply do...

341
Hari Shankar ·

1) If you let t = \frac{y}{x}, then we can reformulate the problem as, under what conditions will the roots of the quadratic, at^2+2ht+b=0 have roots, m and -1/m.

Since product of roots is -1, we must have \frac{b}{a}=-1\Rightarrow a+b=0

2) Now, you can try this one

3) WLOG a<b<cf = \frac{(x-a)(x-c)}{(x-b)}; f: (-\infty, b) \rightarrow \mathbb{R}

It is continuous everywhere in its domain.

Now, as x \rightarrow -\infty , f(x) \rightarrow -\infty and asx \rightarrow b , f(x) \rightarrow \infty

Since its continuous, from Mean Value Theorem f takes all real values.

A similar analysis for (b, \infty) shows us that the given expression takes on every real value at least twice

6
AKHIL ·

these r actually some general derivations so it wud be better if u see them properly!!

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