g(x)=∫3a^2+2bx+c
now g(1)=0
and g(0)=0
so by rolles theorem
atleast one point between 0-1
g'(x)=0
so answer is a
plz solv ethese????
1)if a,b ,c are real a+b+c=0,then quadratic equation 3a^2+2bx+cx=0 has-
a)at lest 1 root in [0,1]
b)at least one root in [1,2]
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2 Answers
akari
·2009-12-29 21:12:08