for real x,the function
(x-a)(x-b) will assume real values provided
x-c
(A) a>b>c (B)a<b<c
(C) a>c>b ( D) a<c<b
please xplain logic...
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for real x,the function
(x-a)(x-b) will assume real values provided
x-c
(A) a>b>c (B)a<b<c
(C) a>c>b ( D) a<c<b
please xplain logic...