Quadratics more....

(1)see here for a solution of x , only the numerator can be zero
so u get x = 2¹⁶

(2) now denominator cant be =0

so we get the condition that x≠2^y4 ...(i)

now one value of x we know is 2¹⁶

so from (i) 2¹⁶ ≠2^y4

so y⁴≠16

so y≠2

so a = 2....(1)

(3) now in the denominator

log₄(log_y(log₂x))) > 0

so x > 2^y

we kno 1 value of x i.e 2¹⁶

this x also satisfies above ineq

so 2¹⁶ > 2^y

so 16 > y

so b = 16...(2)

but i m confused here that from prop of log y≠1 and above i got that y≠2

so wat will be a =?

with bipin sirs help we can safely say a = 2

bcz they want that value of y wich y cannot take btween b and c

bcz if it wasnt the case then we would hav said that a can also be 20 or something

Thanks QWERTY