well i did not solve it completely but at a first sight i feel that it should be
2(b + q) = a2 + p2 - 2
If a, b are roots of cos2x + acocx + b=0 as well as of sin2x + psinx + q, then a, b, p, q satisfy the relation
1)1 + b + a2 = p2 - q - 1
2)a2 + b2 = p2 + q2
3)b + q = a2 + p2 - 2
answer given is 3
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3 Answers
chinmaya
·2011-05-18 23:01:28