roots

real roots of the eqⁿ 7^log₇(x²-4x+5)=x-1 are

5 Answers

This is a quadratic equation.. solve it :)

take 7^log7 = k and proceed !!

x²-4x+5>0 (D < 0)

it can also be written as

x²-4x+5 = x-1

as a^log_ax = x

x²-5x+6 = 0

=> x = 3,2

& x - 1 > 0

=> x > 1

so final ans,

x = 3,2

huh!!
what's the question :O

!!!!

i think it is log to the base 7

not log7.............................

oh.. ok.. got u..

:)
good work :)

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