Roots

try like this..

the sum of 1 roots is not 5 bcos that means 5 will be a rooot...
similar;y sum of 4 roots is not 5 bcos then the 5th root will be -5 (sum of all roots here is zero)

now the sum of 2 roots is 5 or the sum of 2 roots is -5
if the sum of 2 roots is 5, then the real part is 2.5
a, a', b, b', c (where c is a constant)

we have a+a'=5
& b+b'+c=-5 (or vice versa)

aa'+(a+a')(b+b'+c)=0
so aa'=25

a=2.5+ix
so 25/4+x²=25
so = 5√3/2

So one root is \frac{5}{2}(1\pm\sqrt{3}i)

figure out the other roots now :)