if the roots of the equation x2-px+q=0 differ by unity then p2=
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2 Answers
Lokesh Verma
·2008-11-27 00:45:39
x1+x2=p
|x1-x2|=1
x1x2=q
you need to eliminate x1 and x2
(there is a very simple standard trick..) .... just think..
Lokesh Verma
·2008-11-27 01:09:18
(a+b)2=(a-b)2+4ab
use x1 and x2 instead of a and b
so p2=12+4q
p2=1+4q