thats what i posted na bhaiyan.
The number of ways in which the six faces of a cube be painted with six different colours is......
a]6
b]6!
c]6C2
d] none of these
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18 Answers
what is the justification of
now the rest 4 may be put on any of the side faces....they remain identical
no they arent identical..
Bcos the two other faces are fixed..
Try this on a dice
you have 1 and 6 on opposite faces...
Try to reverse the numbering of 2, 3, 4, 5...
You wont get the same dice.
but....one thing....
Now you have 4 colors and 4 faces.. each in a circular part
so the no of ways is 3!=6
here clockwise and anticlockwise arangements are identical....aren't they[7]
then should it be 3!/2[7]
hence the ans 5*3=15...or...6C2
@bhargav..
Sorry dude I was not able to understand the opening up of the cube thing :(
could u elaborate mroe?
@abhirup:
no of ways you can arrange n ppl on a circular table?
(n-1)!
I HAVE A GUD WAY.OPEN UP THE CUBE AND SEE IT AS A CIRCULAR PERMUTATIONS. NOW ANSWER BECOMES 5P2
THATS 30.
it is common sense ....na...
but bhaiyaa... why did you write 3! [7]
i think it shud be 6!...
but i don't think that it wud be so easy....
the colour of the top face may be any of the 6.
now for it the colour of the bottom may be of 5 different.
now the rest 4 may be put on any of the side faces....they remain identical
so...5*6=30
bhaiyaa...i didn't get ur...3!
i m not convinced with my method.....
The 6 faces are independent.
Color one of them and fix that.(and put it at the bottom)
So you have 5 faces left
the top face can be colored in 5 ways.
Now you have 4 colors and 4 faces.. each in a circular part
so the no of ways is 3!=6
so 5.6=30