Tm+n=a+(m+n-1)d
Tm-n=a+(m-n-1)d
add both
Tm+n+Tm-n=2a+(m+n-1+m-n-1)d
=2a+2(m-1)d
=2Tm
Show that the sum of the (m+n)th and (m-n)th terms of an A.P is equal to twice the mth term.
Tm+n=a+(m+n-1)d
Tm-n=a+(m-n-1)d
add both
Tm+n+Tm-n=2a+(m+n-1+m-n-1)d
=2a+2(m-1)d
=2Tm