g.p
how to find the sum of the series-
(1)x2+x4+x6+....+x2n
(2)1/x2+1/x4+...1/x2n.
Please tell in a proper stepwise manner.
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3 Answers
omkar
·2010-05-15 08:46:55
(1) this is a GP with first term = x2 and common ratio =x2
Applying the formula for sum of GP = a(rn-1)/(r-1)
we have S = x2(x2n-1)/(x2-1)
(2) similarly for this one a=1/x2 and r=1/x2 and it is a GP
So, S = x-2(x-2n-1)/(x-2-1)