Hint: Check bounds of LHS
Sum of all the solutions in [0, 4Ï€] of the equation-
tanx + cotx +1 = cos(x + π/4) is ??
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10 Answers
The solution which i am getting in the interval [0, 2Ï€ ] is 3Ï€/4 so similary there will be one more in [2Ï€,4Ï€ ].. 11Ï€/4 sum of both will be 7Ï€/2
See wht i've done....
LHS- Sin2x+Cos2xSinx.Cosx +1
= 2Sin2x + 1
Which can vary frm -1 to infinity fr x in[0,4pi].
Is this much ok...? Wht nxt...?
-1<=sin2x <=1
or, -1>=1/sin2x 1/sin2x>=1
or -1>=LHS and LHS>=3
thus only possibility is LHS=-1
Toh wahi toh kiya naa....? Writing it as 1/Sin2x & chking out the limits.
Or....u mean smthing else...?
Both are same...actually i first did by graphical method...then used differentiation for verification..