surds

1) √10+√5-√3√3+√10-√5=

2)Find the cube root of 9√3+11√2

3 Answers

1) √10+(√5-√3)√10-(√5-√3).

=[√10+(√5-√3)][√10+(√5-√3)][√10+(√5-√3)][√10-(√5-√3)].

=18-2√15+10√2-2√302(1+√15)
we have to rationalise it again with (1-√15).

262

Aditya Bhutra ·2011-04-02 00:05:43

for 2nd case- the expression can be expresed as - (√3 )³ + (√2)³ + 3.√2.√3( √2 +√3 )
hence it is in the form of (a+b)³

or (√2 +√3)³
therefore its cube root is just - √2 + √3

√6+2√333-19√3 =

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