yes.. its the diagonally opposite corner.
A 10 X 10 X 10 cube is formed of small unit cubes. A grasshopper sits at the center O of one the corner cubes. At a given moment it can jump to the center of any of the cubes which has a common face with the cube where it sits, as long as the jump increases the distance between point O and the current position of the grasshopper. How many ways are there for the grasshopper to reach the unit cube at the opposite corner?
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UP 0 DOWN 0 0 3
3 Answers
Surprised this prob is not done yet. Isnt it an extension of the familiar grid problem, where u have to start at one corner and reach the opposite corner with the only allowable moves being to the right and up.
Kaymant sir, here I think it is mean diagonally opposite corner, right?
just a try..
there are total 27 places to move for grass hopper in XYZ space..
i.e 9 in each X,Y,Z direction
=> first choose 9 out of 27..and then choosing remaining 9 out of 18....the remainig will be fixed automatically
=> no. of ways =(27C9)(18C9)