Algebra - three methods interesting one

62

Lokesh Verma ·2009-02-04 10:27:34

¹⁰C₇+¹⁰C₇+¹⁰C₈

First case A attends, B doesnt

2nd B not A

3rd neither..

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11

Subash ·2009-02-04 10:29:31

ok one method is rite

we still have two more methods to solve this one(as far as i know)

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13

Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-02-05 03:14:31

²C₁*¹⁰C₇+²C₀*¹⁰C₈

would u consider this as a different method??

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33

Abhishek Priyam ·2009-02-05 03:18:46

²C₁*¹⁰C₇(sin²x+cos²x)+²C₀*¹⁰C₈

:D

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Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-02-05 03:29:24

²C₁*¹⁰C₇(sin²x+cos²x)+²C₀*¹⁰C₈(ln e )[3]

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11

Subash ·2009-02-05 06:48:55

¹²C₈-¹⁰C₆

10C6 is the num of ways with both included compulsorily

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11

Subash ·2009-02-05 06:51:36

as for the third one

¹⁰C₇+¹¹C₈

1st term is with one attending

and 2nd is one not attending

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Subash ·2009-02-05 06:52:10

@abhirup

no i dont consider them to be diff

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