24yup.....plz explain how........
If a,b,c and u,v,w are 2complex nos. represeting teh vertices of 2 triangles such that
c=(1-r)a+rb and w=(1-r)u+rv where r is a complex no. then what is relation between 2 triangles.
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6 Answers
341c = (1-r)a + rb \Rightarrow c-b = (1-r)(1-a) \Rightarrow \frac{c-b}{a-b} = 1-r
Similarly, \frac{w-v}{u-v} = 1-r
Remember that the sides of the triangle with vertices a,b and c are (a-b), (b-c) and (c-a). Similarly you can write down the sides for the triangle with vertices u,v, w.
So now we have \arg{\frac{c-b}{a-b}} = \arg{\frac{w-v}{u-v}}
Also, \frac{|c-b|}{|a-b|} = \frac{|w-v|}{|u-v|}
Two corresponding sides are proportional and the included angles are equal and hence we have established similarity
1cant we say it jus by looking at d question carefully ??????????? ll there b error in d ans if we do so??????????
341Could you tell us how you deduced similarity by looking carefully at the question? It may help the members.