triangles

c = (1-r)a + rb \Rightarrow c-b = (1-r)(1-a) \Rightarrow \frac{c-b}{a-b} = 1-r

Similarly, \frac{w-v}{u-v} = 1-r

Remember that the sides of the triangle with vertices a,b and c are (a-b), (b-c) and (c-a). Similarly you can write down the sides for the triangle with vertices u,v, w.

So now we have \arg{\frac{c-b}{a-b}} = \arg{\frac{w-v}{u-v}}

Also, \frac{|c-b|}{|a-b|} = \frac{|w-v|}{|u-v|}

Two corresponding sides are proportional and the included angles are equal and hence we have established similarity

cant we say it jus by looking at d question carefully ??????????? ll there b error in d ans if we do so??????????

Could you tell us how you deduced similarity by looking carefully at the question? It may help the members.