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x,y,z are real no such that 0<x,x,z<1 and x+y+z=2,then xyz/(1-x) (1-y) (1-z). can take value?

5 Answers

A subset of (0,1).[6]

Thats all I can infer.

how

Took x,y,z as a/b, c/d, and e/f.

Got ace/(b-a)(d-c)(f-e)

Then tried to maximise it...

srk?

ans is correct,but how?

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