10=n-n
a^0=a^(n-n)
a^0=a^n * a^(-n)=a^n/a^n=1
for any 'n' ....
8 Answers
6o0is inderteminate
beacause
same logic given by prateek
o0 can be written as
01-1
i.e.
0/0
and we all know that 0/0 is indeterminant.
thus it is not defined.
13There is a TiiT Classic on 00...
( http://targetiit.com/iit-jee-forum/posts/10th-january-2009-1565.html )
1Hmmm , pretty good and simple doubt posted here , ...... , nice to see .
As far as ( 0 ) 0 , is concerned , I think the answer can either be 1 or 0 depending on the conditions .
One should probably note that ( 0 ) 0 is actually the single element in the intersection of the sets ,
" 0 n " and " n 0 " , where " n " is any number .
