Recently Active Calculus Questions

√(tanx+2)dx ...

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∫x6 / 1+x5 dx ∫x / 1+x5 dx ...

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∫(x3m+x2m+xm)(2x2m+3xm+6)1/mdx .For any natural no. m, x>0. ...

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∫sec2x/(secx+tanx)9/2 ...

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INTEGRATE: 1) (x3+3)/x6(x2+1). Upper limit=∞;Lower limit=0 2) xe-x/( 1-e-2x ). Upper limit=0;Lower limit=∞. 3) If f(x) be a function satisfying f'(x)=f(x) with f((0)=1 and g be the function satisfying f(x) + g(x)=x2,then ...

Integrate: 1) [(x-1) x4+2x3-x2+2x+1 ]/x2(x+1) 2) (x2-1)/(x3 2x4-2x2+1 ) ...

INTEGRATE: emsin-1x ...

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Integrate: 1) ( sinx )/( sinx + cosx ) 2) xln(x)/(x2-1)3/2. ...

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\hspace{-16}$If $\bf{\mathbb{S} = \sum_{r=4}^{1000000}\frac{1}{r^{\frac{1}{3}}}}.$ Then value of $\bf{\left[\mathbb{S}\right] = }$\\\\\\ where $\bf{[x] = }$ Greatest Integer function ...

Integrate this: \frac{x^{3}sin^{-1}x}{\sqrt{1-x^{2}}} ...

If f(x)=∫xa 1/f(x) dx (x>0) and ∫1a 1/f(x) dx= 2 ,then f(50) is: ...

The minimum value of mod of(sinA + cosA + tanA + secA + cotA + cosecA) is 2 2 -k.Find k ...

PROVE THAT : iim x100ln(x)/extan-1(π/3 + sinx)=∞ x→∞ ...

If f(x) and φ(x) are continuous function in[0,4] satisfying f(x)=f(4-x),φ(x) + φ(4-x)=3 and ∫40f(x)dx=2,then the value of ∫40 f(x)φ(x)dx is: NOTE:The upper and lower limits are 4 and 0 ...

If each ai>0, then the shortest distance between the point(0,-3) and the curve y=1+a1x2 + a2x4 + ...........................................+anx2n is a) 1 b) 2 c) 3 d) 4 ...

Int. x^2 dx/(x^2 + bx +12) ...

If each ai>0, then the shortest distance between the point(0,-3) and the curve y=1+a1x2 + a2x4 + ...........................................+anx2n is a) 1 b) 2 c) 3 d) 4 ...

Given that f is areal valued differentiable function such that f(x)f'(x)<0,for all real x.It fpllows that a) f(x) is an increasing function b) f(x) is a decreasing fnction C) mod(f(x)) is an increasing function d) mod(f(x) ...

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∫sin(4x)etan2x ...

*Image* please show the solution Ans is 25m/s ...