Recently Active Calculus Questions

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hey y u ppl aren't solving my problem.....are u ignoring or u can't solve...pls bother to checkout...they r a set of 10 questions which i hav posted earlier...with title "Question no. 2" and so on..... ...

The number of solution of the equation e2x + ex + e-2x + e-x = 3(e-2x+ ex) is 1. 0 2. 2 3. 1 4. more than 2 ...

The expression wherever defined, sec4x - 4tan3x+ 4tanx is always : 1. positive 2. negative 3. non- positive 4. non negative ...

pls any 1 help me wid the problems ...dat i hav posted....a total of 10 questions...would b very grateful 2 u ...if u solve it..... ...

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from the one u all hate (bindaas) find \lim_{n\rightarrow \infty}\sum_{k=1}^{n}{\frac{1}{k+n^2}} ...

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the number of bijective functions f:A->A,where A={1,2,3} such tht f(1)≠3,f(2)≠1,f(3)≠2 are----?? ...

\boxed{1} \int \frac{(a+bsinx)}{(b+asinx)^n} dx n>2 A DOUBT ...

If 1- x4 + 1- y4 = k(x2 - y2) prove that dy/dx = x 1- x4 / y 1- y4 ...

1. A function f(x) is defined so that for all real x {f(x)}n = f(nx). Prove that f(x).f'(nx) = f'(x).f(nx). ...

Evaluate lim x→∞ (ncr pr qn-r) if np = m , p+q =1 and m,r are contant. ...

\large [x].[y]=x+y\,\rightarrow all\,non\,integer\,sol.\,lies\,on\,exactly\,2\,lines\,find\,them. ...

A point P moves inside a triange A(00),B(1,1/ 3 )and C(2,0) such that min(PA,PB,PC)=1,then the area bounded by the curve traced by P is: a)3 3 -3pi/2. b) 3 +pi/2 c) 3 -pi/2 d)3 3 +3pi/2 ...

especially to ppl who think they r genius ... like 1) shubomoy 2)sanchit 3)जय 4)qwerty prove : \boxed{1} \\ \texttt{{if |x| < 1 , then prove that }} \\ \\ \lim_{n\rightarrow \infty}x^n=0 \\ \\ \boxed{2}\lim_{n\rightarr ...

Suppose p(x) is a polynomial with integer coefficients. The reminder when p(x) is divided by x-1 is 1 and the remainder when p(x) divided by x-4 is 10. If r(s) is the remainder when p(x) is divided by (x-1)(x-4), find the val ...

lim x → pi/2 cos x/ (1-sin x)2 ...

\large find \, the\,no.\,solutions\,of\,\rightarrow \,2^{x}= x^{2}+1 see actually by drawing graph no. of sol. "seems" to be 2....but actually the ans. is 3.....( i checked it on wolfram alpha )......but i want to know how sh ...

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lim x→0 (sin x - tanx )2 + ( 1 - cos 2x )4 + x5/7 tan7 x + sin6 x + 2 .sin5 x i try expanding the numerator by substituting 2sin2x in place of ( 1 - cos 2x ).....am getting stuck after this.... ...