Recently Active Calculus Questions

Form the differential equation satisfied by [1 – x2]1/2 + [1 – y2]1/2 = a.(x – y), a is an arbitrary constant. ...

∫1/(x2+1)(x4+1) ...

∫(sin8x - cos8x)/(1-2sin2xcos2x) ...

∫1/(x2(x4+1)) ...

very small doubt from ncert its from misc exercis last question Q number of binary operations on set {a,b} is?????? ...

Show that the semi vertical angle of a right circular cone of given surface area and maximimum volume is sin-1(1/3) Pls give the shortest method..It is there in RD, but i think it is tooooooo long...I need EXPERT'S Help... ...

Q1. 0∫10 [ (x2+2)/(x2+1) ] dx = (A) 0 (B) 2 (C) 5 (D) none of these ( [.] denotes G.I.F. ) ...

find the area under the curve and make the graph of it also Q For t>0, find the minimum value of 01∫ x |e-x2-t|dx ...

point "A" lies on d curve y=e-x2and has d coordinates{x,e-x2} wer x>0.point B has d coordinates{x,0}.if O iz d origin then the max area of triangle AOB is a)1/√2e b)1/√4e c)1/√e d)1/√8e ...

∫√x /√x3+a3 ...

A technique of solving diffential equations deals with the Laplace Transformations of a function. Let ƒ(t) be a function of 't' defined for all +ve values of t , then 0∫∞ e - st ƒ(t) dt ; is called the Laplace transform ...

∫ f(x)/x3-1 where f(x) is a polynomial of degree 2 in x such that f(0)=f(1)=3f(2)=-3 ...

Board questions..(so pls i need detailed answers.. we cant use graphs in boards for explanations) 1. If f(x) = e1/x, x≠0. and 1 if x=0. Find whether f is contiuous at x=0. 2. f(x) = (x-1) tan Πx/2, if x≠1 and k if x=1. F ...

f(x)=[x] ,x≥0 f(x)=K+[x] ,x<0, {[.] is the greatest integer function......} is continuous at x=0, and one root of ax^{2} +bx+c=0 exceeds the other by K,....then b^2-4ac =? a) a b)b c)a^2 d)b^2 ...

Well what sort of function can be this which satisfy the function rule as f(x+y)=f(x)+f(y)? I mean which function can it be? ...

Q1... Show that the semi-vertical angle of the cone of the maximum volume and of given slant height is tan-1( 2 ). Q2... . Show that semi-vertical angle of right circular cone of given surface area and maximum volume is sin-1 ...

A strong candidate for JEE 2009!! Find \int_0^1 (1-x^{2008})^{\frac{1}{2009}} dx - \int_0^1 (1-x^{2009})^{\frac{1}{2008}} dx ...

\begin{vmatrix} 3x &4x &-5 \\ 2x^{2}&9 &2x \\ x& 8 & 3x \end{vmatrix} = ax^{4}+ bx^{3}+cx^{2}+ dx+e, then, the value of 6a+5b+4c+3d+2e is equal to....... a.273 b.235 c.-15 d.-53 ...

let f(x,y) be a periodic function satisfying the condition f(x,y)=f((2x+2y),(2y-2x)) x,y →R now define a function g by g(x)=f(2x,0) . ...

if y(x-y)2= x then find ∫dx/(x-3y) ...

Find the limit to: *Image* here a,b and c are non zero constants!!!!! ...

0∫1log(1+y)dy/(1+y2) ...

∫(x+√1+x2)ndx ...

SUM1 help me wid this......... \int dx/\sqrt{sin^3xsin(x+\alpha )} ...

let tanθ= limx-0 (cosx+sinx/cosx+sinx.cosx)^{cosecx} then, θ=? a)pi/2 b)pi/3 c)pi/6 d)pi/4 ...

∫√tanx=? ...

Either you will have this in a trice or you will slog it out for several minutes: Evaluate \int_0^1 \frac{(x-b)(x-c)}{(a-b)(a-c)} + \frac{(x-c)(x-a)}{(b-c)(b-a)} + \frac{(x-a)(x-b)}{(c-b)(c-a)} \ dx ...

∫ (√1+x4)dx/(1-x4 ) And haan answer in x and functions only! Ya this sum is xeroxed one so dont be surprised if u si dis in a book ! :-D ...

I have been sitting on this problem for an hr but it will be simple for u guys........ My brain hasn't been working too well after spending 5 days reading biology!!! \int (3x-2)\sqrt{x^{2}+x+1} ...

∫[tan^(-1)x]^2dx limit is 0 to 1 ...