62i think you know where the next point of normal at at^2,2at of a parabola meets
then the distance is given by ....
I guess this should be small only!
1the normal at t meets the other point on the parabla at -t -2/t
calculating the distance and minimising i think u get the ans
1yes, that formula is derived for y2=4ax curve. we can't generalize it !
for this parabola x2=y, let P(t1,t12) and let normal at P meet the parabola again at Q(t2,t22)
since normal is perpendicular to tangent (:P), (slope of normal)x(slope of tangent)=-1
=> (t2-t1)2t1 = -1 => t2= t1 - 1/2t1
i hope it's easy from here. :)
correct me if i am wrong !
24ok............
my method was same as u all...........but i was looking for something even shorter than this...............
anyways thanx...