A special integration problem.Plz solve this one.

If x>0 then integrate (2x-[2x])2 from 0 to 100[x] where [.] means G.I.F.

1 Answers

1357
Manish Shankar ·

{2x}2 periodic with period 1/2

it becomes

200*∫(0 to 1/2) (2x)2

=100/3

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