AD (3)

x=0 =>y=1

after this there are two mthods...
one is assume (1+x)^y=u and sin-1(sin^2x)=v
and doo 1 page of hard wrok

second method is short

(1+x)^y -y+ Sin^-1(sin²x)=0
f(x,y)=0
f_x=y(1+x)^y-1+1√1-sin⁴x2sinxcosx
put x=0,y=1
=>f_x=1

simialrly u will get f_y=-1
slope normal=f_yf_x=-1

=> eqn y-1=-1(x) =>y+x-1=0

mentor ... ur a genius.. :)