yes , this is modified libnitzzzz theorem
& this is one of the most common example of it,
just differentiate wrt a & then integrate , u will get
I = ln(a+1)
I don't if it is in syllabus... But sir taught it...
F(a)=a∫bf(x,a)
F'(a)=a∫bδf(x,a)/δa
Try this out in evaluating 0∫1(xa-1)/lnx
yes , this is modified libnitzzzz theorem
& this is one of the most common example of it,
just differentiate wrt a & then integrate , u will get
I = ln(a+1)