Another one...

IIT JEE 2015 Guidance › Calculus questions › Another one...

Not a dbt.

Let I_1=\int_{0}^{\frac{\pi}{2}}{\frac{sin\alpha cos\alpha}{(\alpha+1)}d\alpha}

I_2=\int_{0}^{\pi}}{ \frac{cos\alpha}{(\alpha+2)^2}d\alpha}.

Find the value of \frac{2I_1+I_2}{2}.

#Mathematics #Calculus

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1 Answers

11

Devil ·2010-05-03 23:11:34

anyone trying?

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