I3>I1>I2
I1=Π/6∫Π/3sinx/x
I2=∫(same limits )sin(tanx)/tanx
I3=∫(same limits)sin(sinx)/sinx
give the relation between I1 I2 and I3
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7 Answers
Hari Shankar
·2009-02-08 00:15:44
The function f(x) = sin x / x is a decreasing function on [0, π/2].
Also tanx > x > sin x in the given interval.
Hence sin(sin x)/ sin x> sin x/ x > sin(tan x)/tan x
Hence I3>I1>I2