Another One...

Bhaiyaa, d/dx(e^x2) = e^x2.2x only naa ?? [186]

I got, g'/g = 2x/(2x-1)

Sloving which, am getting smthing like-
g(x)=K.e^{\frac{2x-1}{2} +\frac{ln(2x-1)}{2}

& On substituting x=1, e = K.e^1/2 => K = e^1/2 Which results in...

g(x)=e^{\frac{2x-1}{2} +\frac{ln(2x-1)}{2}+\frac{1}{2}

Using this, i get 6,

But, the answer is 8......Where am i going wrong?? [2]

Okie got it....! was making a silly mistake...thnx bhaiyaa...