Q1 limx→0[ex-1x]
Q2 limx→0 {ln(1+x)x}
where [.] =GINT
and {.} is fract part
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1 Answers
Tush Watts
·2010-01-12 09:42:28
In both the cases, the limit doesn't exists.
Ans 1) L.H.L = 0
R.H.L = 1
Ans 2) L.H.L = 0
R.H.L = 1