any shortcut ??

Ans is coming but method is very long.. is there any shorter method ??

x³ + y³ = 3axy

P.t d²y/dx² = 2a²xy/(ax-y²)³

5 Answers

whats the ques ???

find dy/dx first..

then express dy/dx in terms of the rest.. then differentiate again..

that only i had done bhaiya..very long..guess there is no alternate method.

x^3+y^3=3axy \\\Rightarrow 3x^2+3y^2(dy/dx) = 3ay+3ax(dy/dx) \\\Rightarrow dy/dx=\frac{ay-x^2}{y^2-ax}

Now just differentiate onece more.. you will get another dy/dx..

just use that...

ya thats d way i finally proceeded bhaiya..thank u.

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