d)1/√8e is the answer ..
point "A" lies on d curve y=e-x2and has d
coordinates{x,e-x2} wer x>0.point B has d
coordinates{x,0}.if O iz d origin then the max area of triangle
AOB is a)1/√2e b)1/√4e c)1/√e d)1/√8e
-
UP 0 DOWN 0 0 2
2 Answers
ANKIT MAHATO
·2009-03-19 19:26:11
{x,e-x2} , {x,0} , {0,0} ...
Area is given by ...
mod(x*(0-0) + x*(0 - e-x2) + 0*(e-x2 - 0) )/2
xe-x2/2 = Area
differentiating this we get
e-x2 - 2x2e-x2 =0
x = 1/√2
putting this in the original eq of area we get the answer .....