Ans C
f(x) = x4
Sry latex nt working..
Find ∫01 f(x) = 1/5 and ∫1√2 √2 - x 2 = Ï€/4 - 1/2 ..add both these areas and then multiply by 2..coz the graph is symmetric abt y axis
The smaller area enclosed by y = f(x) when f(x) is polynomial of least degree satisfying
1/x = e and the circle x2 + y2 = 2 above the x axis is
a) \pi / 2
b) 3/5
c) \pi2 - 35
d) \pi2 + 35
Ans C
f(x) = x4
Sry latex nt working..
Find ∫01 f(x) = 1/5 and ∫1√2 √2 - x 2 = Ï€/4 - 1/2 ..add both these areas and then multiply by 2..coz the graph is symmetric abt y axis