1057@dr.house 2c+b will be 16-4Ï€....
\hspace{-16}$If each side of Square $\mathbf{OABC}$ is $\mathbf{4}\;$unit\\\\ and There are $\mathbf{4}$ Quarter Circle Center at Corrosponding Vertex\\\\ Then Find Area of Region denoted by $\mathbf{\bold{\alpha}}$ and $\mathbf{\beta}$ and $\mathbf{\gamma}$
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3 Answers
39its taking too long to type
in the below answer let
alpha=a
beta=b
gamma=c
fromt he square, a+4b+4c=16
2c+b=4Ï€
a+2b=16-8Ï€
write everything in terms of b and solve it
71β+2γ = 16 - 4 Î
and 2β + α = 8 Π- 16 (8Π> 16)
Note: This question was also posted by Nishant Sir in his EDUDIGM's weekly contest.
