Area-very tough!!!!!!

Find the area bounded by the curves x2+y2=4, y=x2+x+1,
y=[sin2(x/4)+cos(x/4)] and the x-axis,where [.] denotes greatest integer function!!

44 Answers

62
Lokesh Verma ·

i dont think so vishal :(

1
greatvishal swami ·

it can b rearranged to [-(cosx/4-1)2+5/4]
its eql to 1 for x=0,120,180,240,360 deg.

62
Lokesh Verma ·

it can b rearranged to [-(cosx/4-1)2+5/4]

what about when cos x=-1??

ie when x=180 degree
check for that agian

1
Pavithra Ramamoorthy ·

i think no curve exist y=x2+x+1...
he he he...

62
Lokesh Verma ·

but u need to worry about a lot of points that u havve not found anything dear...

I was only pointing that this solution u are giving has mistakes.. find them ...

1
greatvishal swami ·

hey wait 3rd 1 is a fnc

1
Pavithra Ramamoorthy ·

ll d area bounded b equal 2 area bounded by d circle wit x axi???????????????????????????????? plz don scold........

1
greatvishal swami ·

cheak dis for 3rd curve
btw 0-120 deg
1. value of cosx/4 willl be +ve
2.max val will be .8660 for which curv =1
3. for other val in btw cosx/4 ->1 so cosx/4-1 -->0 hence curve will be 1

*** othr values chkd by log table (sry)

1
greatvishal swami ·

acc to me make green line horizontal passing through y=1 for x=-120 to120
then the required area will be quite obvious

1
Pavithra Ramamoorthy ·

i think its equal 2 d area bounded by d circle................

1
greatvishal swami ·

r u still jokin

1
greatvishal swami ·

then make urself clear
i mean some reason

1
Pavithra Ramamoorthy ·

Warning! The integral is not always equal to the area!!

1
Parul Kohli ·

Plz help me to understand howz that graph is possible

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