99 Ques ka answer -1/2 aa raha hai
TARIKA 1
use l hospital(thoda mushkil hoga)
TARIKA 2
sin-1x ko tan-1(√1-x2/x) likh kar formula use kar le (not preferred ..... lamba padega)
TARIKA3
simply use expansion[1]
Q1. lim(x→2a) [√x-2a + √x - √2a]/[√x2-4a2]
Q2. lim(x→∞)2x(√x2+1 - x)
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85 Answers
98 Ques mein simply use
[x]=x-{x}
upper niche highest coeff le leo
answer should be
x/2(edited) sorry choti si mistake ho gaya but the funda should be CLEAR
1st term to 1∞ form hai
i have told u earlier in post 41 how to solve that
2nd term pe la hospital laga de
3rd bhi 1∞form hai
ans is 1 -1/2+1
i.e
3/2
99 , do it by taking expansions of sin-1x and tan-1x and sinx
i mean binomial expansions
Q 98 IS DIRECT SANDWICH THOREM NA...........................................
yes 65 is correct...
i know we can use l'hospital for 0/0 or ∞/∞ form...
aur ek aur baat we can use la hospital when we have o/o form OR∞/∞ form
ashish check the steps if we r wrong then tell us
we cant do anything about the answers given to u
yes explain.... i will explain my answer later.... matlab in 20 mins time...
YEP I KNOW .. CHUMA POSTED... DATZ Y I ROTE STD. 1 ,,,,, I DEL. IT NOW ...........
guys post any questions that u have but please number them accordingly....
iitcomin its obvios dude, use wat we call asa SANDWICH THEOREM. its a direct answer.
sry even u posted a question... shud i del. mine .. itll bcome mess....[2][2][2][2]
second one jus multiply upar-niche with conjugate..
then u will know wat u need to do...
ans is 1.