concept?

if f(x)=âˆš(x-m+1), for x in [m-1,m), m=integer,then evaluate

where n=natural number.

1 Answers

if x lies in [m-1, m)

then [x]=m-1

and x-(m-1)=x-[x]={x}

So f(x)=√{x}

This is periodic by period 1.

So the integral is n times integral from 0 to 1 of √{x}

Which is same as n times integral of √x which is 2/3

so the answer is 2n/3

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