Thanks
f(x) = x - l x - x2 l
x ε [ -1 , 1]
Then the no of points at which f(x) is discontinuos
(A) 2
(B) 1
(C) 0
(D) None
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UP 0 DOWN 0 0 2
2 Answers
Ricky
·2010-05-23 06:24:31
Let us construct the function .
f ( x ) = x 2 , whenever x ≥ x 2 , i . e , whenever x lies between 0 to 1 .
= 2x - x 2 , whenever x ≤ x 2 , i . e , whenever x lies between - 1 to 0 .
Clearly , x = 0 is the only critical point .
But , both the R . H . L and L . H . L have the same value as the functional value at x = 0 ,
i.e , both are zero at x = 0 .
So the function has zero number of discontinuities .