Yes Vivek I am also not Getting The answer in that format.
\hspace{-16}\mathbf{\int_{1}^{\infty}\frac{(x^3+3)}{x^6.(x^2+1)}dx=\frac{a+b\pi}{c}}$.\\\\\\ Then $\mathbf{(a,b,c)=}$
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\hspace{-16}\mathbf{\int_{1}^{\infty}\frac{(x^3+3)}{x^6.(x^2+1)}dx=\frac{a+b\pi}{c}}$.\\\\\\ Then $\mathbf{(a,b,c)=}$