definite Integral (4 April)

\hspace{-16}\bf{\int_{0}^{1}x^{2012}.(1-x)^{2012}dx}

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Vivek @ Born this Way ·

\int_{0}^{1} (1-x)^{2012} . x^{2012} \mathrm{d}x = \beta(2013,2013) = \frac{2012! . 2012!}{4025!}

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