3x=sinθ
dx=cosθdθ
I=\int_{0}^{\pi /2}{\frac{cos\theta d\theta }{2(1+sin(\theta /2))}}
which is now integrable form.
4 Answers
3
1one thing how did you know it was
(sinθ/2 - cosθ/2)2 and not (cosθ/2 - sinθ/2)2 ??
in precise words what happened to the | |
3mmm yes,i agree. then i have to split the integral.
dat may also be a reason for no pink. :P