11dude
replace x by 1/x
u will get
∫012x5(1+3x3)dx/1+x2
now put 1+x2=t
numerator ko aise hi t main bana lena
nicche waala t upper se kaat kar
ek simple polynomial ko integrate karna hoga
i hope u could solve the rest
6 Answers
11
1not zero,how can it be zero when the function is always positive in the given range?
1i took x=tan@
so dx=sec^2@d@
limitz frm pi/4 to pi/2
u egt int of
cot^3@(1+3cot^3@)d@
1thanks manipal,that substitution did the trick,also made the limits 0 to 1!!
!!
if u go the trig way ,u hit a dead end as shown above,thats what i was doing before !!
1ans 9/2+log 2.
i have solved it completely but it is too lengthy to b posted. if it is right then the method i used is dividing the numerator and deno and then substituting it by other variable. use it n still if u can't get the ans then i'll post d solution.